1A^2+5A-10=4

Solution for 1A^2+5A-10=4 equation:

Simplifying
1A2 + 5A + -10 = 4

Reorder the terms:
-10 + 5A + 1A2 = 4

Solving
-10 + 5A + 1A2 = 4

Solving for variable 'A'.

Reorder the terms:
-10 + -4 + 5A + 1A2 = 4 + -4

Combine like terms: -10 + -4 = -14
-14 + 5A + 1A2 = 4 + -4

Combine like terms: 4 + -4 = 0
-14 + 5A + 1A2 = 0

Factor a trinomial.
(-7 + -1A)(2 + -1A) = 0

Subproblem 1
Set the factor '(-7 + -1A)' equal to zero and attempt to solve:

Simplifying
-7 + -1A = 0

Solving
-7 + -1A = 0

Move all terms containing A to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + -1A = 0 + 7

Combine like terms: -7 + 7 = 0
0 + -1A = 0 + 7
-1A = 0 + 7

Combine like terms: 0 + 7 = 7
-1A = 7

Divide each side by '-1'.
A = -7

Simplifying
A = -7
Subproblem 2
Set the factor '(2 + -1A)' equal to zero and attempt to solve:

Simplifying
2 + -1A = 0

Solving
2 + -1A = 0

Move all terms containing A to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1A = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1A = 0 + -2
-1A = 0 + -2

Combine like terms: 0 + -2 = -2
-1A = -2

Divide each side by '-1'.
A = 2

Simplifying
A = 2
Solution
A = {-7, 2}